Forum Replies Created

Viewing 6 posts - 1 through 6 (of 6 total)
  • Author
    Posts
  • in reply to: POG 2 input needed #123026

    I’ve been messing around on mine to enhance my acoustic bass.
    What I’ve discovered is that you have to be subtle.
    I started by finding what was closest to my clean sound – just the dry output.

    Then tried adding single octaves at a time and also removing the dry sound.

    After that you can try various swells and setting for the filter on the POG2. I suggest cahining it with a good EQ especially for the lower register stuff.

    I can do a passable guitar sound and various synth and organ sounds using this approach. I also had a nose at what the band Royal Blood do – the lead in that band is a single bass and he uses two POG 2 s to get guitar like sounds for solo and overdriven guitar. Well worth checking out.

    ok so I replaced the resistor before the A anode connection for the LED on the bypass board with a J175 p-channel JFET:-

    a(L)—-> Resistor>–circuit
    C—circuit

    changes to

    a(L)—>J175 SOURCE J175 GATE —> Circuit (the J175 replaces the resistor, the gate reacts to voltage to switch off)

    J175 DRAIN —-> C —-> circuit (this is the ground connection of the JFET)

    This made A switched ground – I connected C4 The LED ground connection to A

    I took the main effect board out and ran two leads for +9v Red and 0V (-) Gnd across the other side of the board – (see pic)
    C1, C2 , C5 and C6 connected as appropriate.
    C3 isn’t required.

    It works faultlessly and the LED comes on correctly.

    I’m going to try using a J175 P Channel JFET as a switch for the LED ground. They are very cheap. I’m going to put it on the led terminals on a stompville board (very similar to the mammoth one) and use it to switch the led ground connection (C4). I’ll post more when I’ve tried it.

    in reply to: Soft-touch/Silent Switches on POG2 Bypass #122838

    I think the LED would need to have the anode(+) lead disconnected from the pog2 original board and connected to the LED point (+) on the new board. this looks pretty awkward to be honest, but possible.

    The 9v positive needs to connect +9v centre pin on the incoming power. Anywhere on the board connected to this centre pin would be good.

    A relay which replicated the 3pdt would be better. Most of the kits are 2pdt with led direct from the kit board.

    Hi I’ve been looking at the same thing
    I plugged in two balanced leads. The results were different with the input pulled out!

    With the the unit off I checked which of 1 to 6 were connected to ground (ie the input lead ground) and which to the input tip, with the switch in both positions. The ring on both sockets is connected to ground.

    So using the 9 solder points on the pog2 switch pcb, looking at the way they were connected and using a multimeter:-

    with switch in bypass
    C2 is connected to C3 & ground
    input tip goes to C1 is connected to C5 and output tip

    with the effect on
    input tip connects to C1 is connected to C2
    C4 is connected to C3 and ground
    C6 is connected to C5 and output tip

    so from this
    C1 is input
    C2 effect send (gets pulled to ground during bypass)
    C3 is ground
    C4 is pulled to ground when the effect is on – assume this is to connect the LED to ground
    C5 is output
    C6 is effect return

    The only thing that bothers me about this is the LED (C4) connection is just a ground connection and the LED is on the main board.

    Really hope this helps

Viewing 6 posts - 1 through 6 (of 6 total)